What is the solution for (dy)/(dx)=(x^2y^2)/(1+y) ?

The solution for (dy)/(dx)=(x^2y^2)/(1+y) is y= 1/(\W((1){e^{\frac{x^3+c_{1})/3}})}

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(dy)/(dx)=(x^2y^2)/(1+y)

\frac{d y}{d x} = \frac{x ^{2} y ^{2}}{1 + y}

y = \frac{1}{W ( \frac{1}{e ^{\frac{x ^{3} + c _{1}}{3}}} )}

Solution steps

\frac{d y}{d x} = \frac{x ^{2} y ^{2}}{1 + y}

Solve separable ODE:

y = \frac{1}{W ( \frac{1}{e ^{\frac{x ^{3} + c _{1}}{3}}} )}

y = \frac{1}{W ( \frac{1}{e ^{\frac{x ^{3} + c _{1}}{3}}} )}

x \to 2 - lim (4 x - 5)

y = 2 e^{x} - e^{x + 1} + e^{\frac{2}{3}} - 5 π^{2}

y^{^{'}} + 10 y = 6

4 t^{2} - 5 sin (3 t)

\int_{0}^{5} \frac{3 x - 4}{x + 1} d x

What is the solution for (dy)/(dx)=(x^2y^2)/(1+y) ?
The solution for (dy)/(dx)=(x^2y^2)/(1+y) is y= 1/(\W((1){e^{\frac{x^3+c_{1})/3}})}