What is the limit as x approaches 0-of 1/(x^2)-1/x ?

The limit as x approaches 0-of 1/(x^2)-1/x is infinity

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limit as x approaches 0-of 1/(x^2)-1/x

x \to 0 - lim (\frac{1}{x ^{2}} - \frac{1}{x})

\infty

Solution steps

x \to 0 - lim (\frac{1}{x ^{2}} - \frac{1}{x})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 - lim (\frac{1}{x ^{2}}) - x \to 0 - lim (\frac{1}{x})

x \to 0 - lim (\frac{1}{x ^{2}}) = \infty

x \to 0 - lim (\frac{1}{x}) = - \infty

= \infty - (- \infty)

Apply Infinity Property:

\infty + \infty = \infty

= \infty

\int_{1}^{3} e^{x^{2}} d x

\int_{1}^{b} \frac{1}{( x + 1 ) ^{2}} d x

\int 2 e^{- 4 x} d x

\int \frac{1 - x}{x} d x

y = e^{6 x} cos (π x), (0, 1)

What is the limit as x approaches 0-of 1/(x^2)-1/x ?
The limit as x approaches 0-of 1/(x^2)-1/x is infinity