What is (\partial)/(\partial x)(-3xy) ?

The answer to (\partial)/(\partial x)(-3xy) is -3y

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(\partial)/(\partial x)(-3xy)

\frac{\partial}{\partial x} (- 3 x y)

- 3 y

Solution steps

\frac{\partial}{\partial x} (- 3 x y)

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 y \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= - 3 y \cdot 1

Simplify

= - 3 y

\int cos^{4} (5 - x) sin (5 - x) d x

\frac{d y}{d x} = \frac{3 + y}{1 - 2 x}, y (0) = 0

y^{^{''}} - 3 y^{^{'}} = - 6 x + 4

x^{2} - 4 x, x = 0

\frac{d}{d x} (\frac{A + B x + C x ^{2}}{x ^{2}})

What is (\partial)/(\partial x)(-3xy) ?
The answer to (\partial)/(\partial x)(-3xy) is -3y