What is the integral of sin^5(x)cot(x) ?

The integral of sin^5(x)cot(x) is (sin^5(x))/5+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of sin^5(x)cot(x)

\int sin^{5} (x) cot (x) d x

\frac{sin ^{5} ( x )}{5} + C

Solution steps

\int sin^{5} (x) cot (x) d x

Rewrite using trig identities

= \int sin^{4} (x) cos (x) d x

Apply u-substitution

: \int u^{4} d u

= \int u^{4} d u

Apply the Power Rule

: \frac{u ^{5}}{5}

= \frac{u ^{5}}{5}

Substitute back

u = sin (x)

= \frac{sin ^{5} ( x )}{5}

Add a constant to the solution

= \frac{sin ^{5} ( x )}{5} + C

\frac{ln ( t )}{t}

\int \frac{x ^{2} - 256}{x} d x

x = - 3, x = 4, y = e^{2 x}, y = 2 e^{- x}

\frac{d}{d x} (x^{m} a^{2} - x^{2})

\frac{\partial}{\partial x} (x^{2} + 8 x y + 17 y^{2} - 2 y + 1)

What is the integral of sin^5(x)cot(x) ?
The integral of sin^5(x)cot(x) is (sin^5(x))/5+C