What is the integral from 1 to t of (31)/(x^3) ?

The integral from 1 to t of (31)/(x^3) is 31(-1/(2t^2)+1/2)

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integral from 1 to t of (31)/(x^3)

\int_{1}^{t} \frac{31}{x ^{3}} d x

31 (- \frac{1}{2 t ^{2}} + \frac{1}{2})

Solution steps

\int_{1}^{t} \frac{31}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 31 \cdot \int_{1}^{t} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{1}^{t}

= 31 [- \frac{1}{2 x ^{2}}]_{1}^{t}

Compute the boundaries:

- \frac{1}{2 t ^{2}} + \frac{1}{2}

= 31 (- \frac{1}{2 t ^{2}} + \frac{1}{2})

x \to 0 lim (\frac{ln ^{2} ( x )}{x})

f (x) = ln^{3} (3 x - 5)

\int sec^{2} (t) + t (t^{2} + 1)^{3} + t^{2} ln (t) d t

\frac{d}{d x} (e^{s i n (3 x)})

y^{^{'}} - 2 y = 2 - 4 x

What is the integral from 1 to t of (31)/(x^3) ?
The integral from 1 to t of (31)/(x^3) is 31(-1/(2t^2)+1/2)