What is the derivative of y=ln(x^2+3) ?

The derivative of y=ln(x^2+3) is (2x)/(x^2+3)

What is the first derivative of y=ln(x^2+3) ?

The first derivative of y=ln(x^2+3) is (2x)/(x^2+3)

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derivative of

y = ln (x^{2} + 3)

\frac{2 x}{x ^{2} + 3}

Solution steps

\frac{d}{d x} (ln (x^{2} + 3))

Apply the chain rule:

\frac{1}{x ^{2} + 3} \frac{d}{d x} (x^{2} + 3)

= \frac{1}{x ^{2} + 3} \frac{d}{d x} (x^{2} + 3)

\frac{d}{d x} (x^{2} + 3) = 2 x

= \frac{1}{x ^{2} + 3} \cdot 2 x

Simplify

\frac{1}{x ^{2} + 3} \cdot 2 x : \frac{2 x}{x ^{2} + 3}

= \frac{2 x}{x ^{2} + 3}

n = 1 \sum \infty \frac{n !}{10 0 ^{n}}

\frac{d}{d x} (sin (5 x) + tan (3 x))

x^{^{''}} + 2 x^{^{'}} + 10 = e^{- t}, x (0) = 0, x^{^{'}} (0) = 0

\int_{4}^{\infty} 8 x^{- 3} d x

What is the derivative of y=ln(x^2+3) ?
The derivative of y=ln(x^2+3) is (2x)/(x^2+3)
What is the first derivative of y=ln(x^2+3) ?
The first derivative of y=ln(x^2+3) is (2x)/(x^2+3)