What is the derivative of 2cos(x+(cos(x))^2) ?

The derivative of 2cos(x+(cos(x))^2) is -2sin(x)-sin(2x)

What is the first derivative of 2cos(x+(cos(x))^2) ?

The first derivative of 2cos(x+(cos(x))^2) is -2sin(x)-sin(2x)

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\frac{d}{d x} (2 cos (x) + (cos (x))^{2})

- 2 sin (x) - sin (2 x)

Solution steps

\frac{d}{d x} (2 cos (x) + (cos (x))^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 cos (x)) + \frac{d}{d x} ((cos (x))^{2})

\frac{d}{d x} (2 cos (x)) = - 2 sin (x)

\frac{d}{d x} ((cos (x))^{2}) = - sin (2 x)

= - 2 sin (x) - sin (2 x)

y^{^{'}} = \frac{y ^{4} x ^{4} + 4 x ^{4}}{y ^{3}}

\int \frac{x + 7}{x ^{2} ( x + 2 )} d x

\frac{d}{d x} (\frac{cos ( x ) 2 x ^{3}}{e ^{x}})

\int e^{2 x} sin (- 3 x) d x

x \to + \frac{1}{5} lim (2 + ∣ 5 x - 1 ∣)

What is the derivative of 2cos(x+(cos(x))^2) ?
The derivative of 2cos(x+(cos(x))^2) is -2sin(x)-sin(2x)
What is the first derivative of 2cos(x+(cos(x))^2) ?
The first derivative of 2cos(x+(cos(x))^2) is -2sin(x)-sin(2x)