What is the derivative of y=7sin(4x) ?

The derivative of y=7sin(4x) is 28cos(4x)

What is the first derivative of y=7sin(4x) ?

The first derivative of y=7sin(4x) is 28cos(4x)

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derivative of

y = 7 sin (4 x)

28 cos (4 x)

Solution steps

\frac{d}{d x} (7 sin (4 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (sin (4 x))

Apply the chain rule:

cos (4 x) \frac{d}{d x} (4 x)

= cos (4 x) \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= 7 cos (4 x) \cdot 4

Simplify

= 28 cos (4 x)

\frac{\partial}{\partial y} (x^{2} y^{5})

x \to 1 + lim (- 2)

y^{^{'}} + 2 y = x^{2} y^{3}

f (x) = x^{9} e^{x}

\frac{d}{d x} (in x^{2})

What is the derivative of y=7sin(4x) ?
The derivative of y=7sin(4x) is 28cos(4x)
What is the first derivative of y=7sin(4x) ?
The first derivative of y=7sin(4x) is 28cos(4x)