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Popular >

y^'=e^{-3x}

Solution

y^{^{'}} = e^{- 3 x}

Solution

y = - \frac{1}{3} e^{- 3 x} + c_{1}

Solution steps

y^{'} (x) = e^{- 3 x}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int e^{- 3 x} d x

\int e^{- 3 x} d x = - \frac{1}{3} e^{- 3 x} + c_{1}

y = - \frac{1}{3} e^{- 3 x} + c_{1}

Popular Examples

limit as x approaches 5 of (|x-5|)/(x-5)

x \to 5 lim (\frac{∣ x - 5 ∣}{x - 5})

integral from 1 to 5 of x^2ln(x)

\int_{1}^{5} x^{2} ln (x) d x

(dy)/(dx)= 1/5 (8-y)

\frac{d y}{d x} = \frac{1}{5} (8 - y)

inverse oflaplace 1-1/(1+x)inverse laplace

1 - \frac{1}{1 + x}

derivative of 4x^2sqrt(5x+1)

\frac{d}{d x} (4 x^{2} 5 x + 1)

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{-3x} ?
The solution for y^'=e^{-3x} is y=-1/3 e^{-3x}+c_{1}