What is (\partial)/(\partial x)(2ysin(x)+e^{2z}) ?

The answer to (\partial)/(\partial x)(2ysin(x)+e^{2z}) is 2ycos(x)

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(\partial)/(\partial x)(2ysin(x)+e^{2z})

\frac{\partial}{\partial x} (2 y sin (x) + e^{2 z})

2 y cos (x)

Solution steps

\frac{\partial}{\partial x} (2 y sin (x) + e^{2 z})

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 y sin (x)) + \frac{\partial}{\partial x} (e^{2 z})

\frac{\partial}{\partial x} (2 y sin (x)) = 2 y cos (x)

\frac{\partial}{\partial x} (e^{2 z}) = 0

= 2 y cos (x) + 0

Simplify

= 2 y cos (x)

x \to 0 - lim (e^{- \frac{7}{x}})

\int - \frac{1}{2 x x ^{2} + 9} d x

e^{x^{5}} + lo g_{4} (π)

n \to \infty lim (\frac{a}{n})

\int \frac{( x ^{2} + 1 )}{2 x} d x

What is (\partial)/(\partial x)(2ysin(x)+e^{2z}) ?
The answer to (\partial)/(\partial x)(2ysin(x)+e^{2z}) is 2ycos(x)