What is the derivative of (x^2/(7x+4)) ?

The derivative of (x^2/(7x+4)) is (7x^2+8x)/((7x+4)^2)

What is the first derivative of (x^2/(7x+4)) ?

The first derivative of (x^2/(7x+4)) is (7x^2+8x)/((7x+4)^2)

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\frac{d}{d x} (\frac{x ^{2}}{7 x + 4})

\frac{7 x ^{2} + 8 x}{( 7 x + 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{7 x + 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) ( 7 x + 4 ) - \frac{d}{d x} ( 7 x + 4 ) x ^{2}}{( 7 x + 4 ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (7 x + 4) = 7

= \frac{2 x ( 7 x + 4 ) - 7 x ^{2}}{( 7 x + 4 ) ^{2}}

Expand

2 x (7 x + 4) - 7 x^{2} : 7 x^{2} + 8 x

= \frac{7 x ^{2} + 8 x}{( 7 x + 4 ) ^{2}}

\frac{\partial}{\partial y} (x^{2} \cdot y)

\frac{d}{d x} (\frac{4 x}{6 x - 1})

x \to 4 lim (2 x - 7)

\int b x^{2} d x

(\frac{2}{( 1 + x ) ^{3}})^{^{'}}

What is the derivative of (x^2/(7x+4)) ?
The derivative of (x^2/(7x+4)) is (7x^2+8x)/((7x+4)^2)
What is the first derivative of (x^2/(7x+4)) ?
The first derivative of (x^2/(7x+4)) is (7x^2+8x)/((7x+4)^2)