What is laplacetransform 4cos(5t) ?

The answer to laplacetransform 4cos(5t) is (4s)/(s^2+25)

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laplacetransform 4cos(5t)

laplace transform

4 cos (5 t)

\frac{4 s}{s ^{2} + 25}

Solution steps

L {4 cos (5 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 4 L {cos (5 t)}

L {cos (5 t)} : \frac{s}{s ^{2} + 25}

= 4 \cdot \frac{s}{s ^{2} + 25}

Refine

4 \frac{s}{s ^{2} + 25} : \frac{4 s}{s ^{2} + 25}

= \frac{4 s}{s ^{2} + 25}

y^{^{'}} + y = 3

\frac{5 x}{x - 2}

y^{^{'}} = 6 x 9 - y^{2}

y^{^{'}} = 1 + x + y^{2} + x y^{2}

x \to \infty lim (\frac{3 ^{x + 4}}{8 ^{x}})

What is laplacetransform 4cos(5t) ?
The answer to laplacetransform 4cos(5t) is (4s)/(s^2+25)