What is the tangent of f(x)=-3x^2-2x,\at x=2 ?

The tangent of f(x)=-3x^2-2x,\at x=2 is y=-14x+12

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tangent of f(x)=-3x^2-2x,\at x=2

tangent of

f (x) = - 3 x^{2} - 2 x, at x = 2

y = - 14 x + 12

Solution steps

Find the tangent point:

(2, - 16)

Find the slope of

f (x) = - 3 x^{2} - 2 x : \frac{df ( x )}{d x} = - 6 x - 2

Compute the slope of

f (x) = - 3 x^{2} - 2 x

x = 2 : m = - 14

Find the line with slope m=

- 14

and passing through

(2, - 16) : y = - 14 x + 12

y = - 14 x + 12

n = 0 \sum \infty (\frac{4}{10})^{n}

\int_{2}^{3} 21 t^{2} d t

n = 1 \sum \infty \frac{n ^{4} x ^{3 n}}{5 ^{3 n}}

\frac{d}{d x} (4 x + 12 y, 12 x - 3 y)

What is the tangent of f(x)=-3x^2-2x,\at x=2 ?
The tangent of f(x)=-3x^2-2x,\at x=2 is y=-14x+12