What is the slope of y=(x^3+1)/(6x),x=1 ?

The slope of y=(x^3+1)/(6x),x=1 is 1/6

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slope of y=(x^3+1)/(6x),x=1

slope

y = \frac{x ^{3} + 1}{6 x}, x = 1

\frac{1}{6}

Solution steps

y = \frac{x ^{3} + 1}{6 x}

In order to find the slope of the function, take the derivative of

\frac{x ^{3} + 1}{6 x}

\frac{d}{d x} (\frac{x ^{3} + 1}{6 x}) = \frac{2 x ^{3} - 1}{6 x ^{2}}

\frac{2 x ^{3} - 1}{6 x ^{2}}

Find the value of

\frac{2 x ^{3} - 1}{6 x ^{2}}

for

x = 1 : \frac{1}{6}

\frac{1}{6}

y^{^{'}} + 4 y = e^{- x}, y (0) = 10

\int_{0}^{6} \frac{1}{∣ x - 3 ∣} d x

\frac{d}{d x} (x (x^{2} + 3)^{3})

y^{^{''}} + 9 y = 2 x^{2} - 5

x \to 1 lim (\frac{x ^{10} - 1}{x - 1})

What is the slope of y=(x^3+1)/(6x),x=1 ?
The slope of y=(x^3+1)/(6x),x=1 is 1/6