What is the integral from 0 to 3 of 2x ?

The integral from 0 to 3 of 2x is 9

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integral from 0 to 3 of 2x

\int_{0}^{3} 2 x d x

9

Solution steps

\int_{0}^{3} 2 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{3} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{3}

= 2 [\frac{x ^{2}}{2}]_{0}^{3}

Compute the boundaries:

\frac{9}{2}

= 2 \cdot \frac{9}{2}

Simplify

= 9

x \to \frac{1}{2} π lim (tan (x))

t \frac{d y}{d t} = t^{3} + 19 t^{3} y

s^{2}

x \to (- 1) + lim (x + 1)

x \to \frac{1}{3} lim (3 x + \frac{1}{4})