What is the sum from n=2 to infinity of (-0.875)^n ?

The sum from n=2 to infinity of (-0.875)^n is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=2 to infinity of (-0.875)^n

n = 2 \sum \infty (- 0.875)^{n}

converges

Solution steps

n = 2 \sum \infty (- 0.875)^{n}

Apply Series Ratio Test:

converges

= converges

\int (\frac{1}{2}) d x

\frac{d}{d x} (e^{- 2.5 x^{2}})

\int p (p + 3)^{4} d p

\int_{- \infty}^{0} e^{x} d x

\int \frac{x + 3}{x ^{2} + 6 x + 10} d x

What is the sum from n=2 to infinity of (-0.875)^n ?
The sum from n=2 to infinity of (-0.875)^n is converges