What is the tangent of y= 1/(4+3x),(2, 1/10) ?

The tangent of y= 1/(4+3x),(2, 1/10) is y=-3/100 x+4/25

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tangent of y= 1/(4+3x),(2, 1/10)

tangent of

y = \frac{1}{4 + 3 x}, (2, \frac{1}{10})

y = - \frac{3}{100} x + \frac{4}{25}

Solution steps

Find the slope of

y = \frac{1}{4 + 3 x} : \frac{d y}{d x} = - \frac{3}{( 4 + 3 x ) ^{2}}

Compute the slope of

y = \frac{1}{4 + 3 x}

(2, \frac{1}{10}) : m = - \frac{3}{100}

Find the line with slope m=

- \frac{3}{100}

and passing through

(2, \frac{1}{10}) : y = - \frac{3}{100} x + \frac{4}{25}

y = - \frac{3}{100} x + \frac{4}{25}

\int x \cdot sec^{2} (3 x) d x

\frac{\partial}{\partial x} (cos (t))

8 (sin (x))^{x}

\frac{d}{d x} (\frac{1}{ln ( x )})

n = 1 \sum \infty 3 (\frac{7}{2})^{n - 1}

What is the tangent of y= 1/(4+3x),(2, 1/10) ?
The tangent of y= 1/(4+3x),(2, 1/10) is y=-3/100 x+4/25