What is the derivative of f(x)=x\sqrt[3]{2+3x} ?

The derivative of f(x)=x\sqrt[3]{2+3x} is cube root of 2+3x}+x/((2+3x)^{2/3)

What is the first derivative of f(x)=x\sqrt[3]{2+3x} ?

The first derivative of f(x)=x\sqrt[3]{2+3x} is cube root of 2+3x}+x/((2+3x)^{2/3)

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derivative of

Solution steps

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

\frac{d x}{d x} = 1

Simplify

\int \frac{x}{2 x - 5} d x

y = \frac{1}{x} (1.1)

\int \frac{x}{x ^{2} - 4 x + 4} d x

\int \frac{- 8 x - 9}{x ^{9}} d x

What is the derivative of f(x)=x\sqrt[3]{2+3x} ?
The derivative of f(x)=x\sqrt[3]{2+3x} is cube root of 2+3x}+x/((2+3x)^{2/3)
What is the first derivative of f(x)=x\sqrt[3]{2+3x} ?
The first derivative of f(x)=x\sqrt[3]{2+3x} is cube root of 2+3x}+x/((2+3x)^{2/3)