What is the integral of 2/(3\sqrt[3]{2x)} ?

The integral of 2/(3\sqrt[3]{2x)} is 2/3 \sqrt[3]{(x^2)/2}+1/(3\sqrt[3]{2)}x^{2/3}+C

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integral of 2/(3\sqrt[3]{2x)}

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply Integration By Parts

Simplify

Add a constant to the solution

f (x) = \frac{1}{x ln ( x )}

\int_{0}^{x} a^{2} - t^{2} d t

\frac{d}{d x} (x^{2} - 25)

sin (7 x) + cos (6 x), at \frac{π}{6}

y = x^{2} 8 + x

What is the integral of 2/(3\sqrt[3]{2x)} ?
The integral of 2/(3\sqrt[3]{2x)} is 2/3 \sqrt[3]{(x^2)/2}+1/(3\sqrt[3]{2)}x^{2/3}+C