What is the integral of cosh(x/(27.2632)) ?

The integral of cosh(x/(27.2632)) is 27.2632sinh(0.03667…x)+C

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integral of cosh(x/(27.2632))

\int cosh (\frac{x}{27.2632}) d x

27.2632 sinh (0.03667 \dots x) + C

Solution steps

\int cosh (\frac{x}{27.2632}) d x

Apply u-substitution

: \int cosh (u) \frac{1}{0.03667 \dots} d u

= \int cosh (u) \frac{1}{0.03667 \dots} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{0.03667 \dots} \cdot \int cosh (u) d u

Simplify

= 27.2632 \cdot \int cosh (u) d u

Use the common integral:

\int cosh (u) d u = sinh (u)

= 27.2632 sinh (u)

Substitute back

u = \frac{x}{27.2632}

= 27.2632 sinh (\frac{x}{27.2632})

Simplify

= 27.2632 sinh (0.03667 \dots x)

Add a constant to the solution

= 27.2632 sinh (0.03667 \dots x) + C

f (x) = x^{3} (x^{2} - 4)

\frac{d}{d x} (\frac{x ^{4} e ^{x}}{4 ^{x} + 3})

\int cos (x) 1 + cos^{2} (x) d x

n = 2 \sum \infty \frac{2}{n ( n - 1 )}

\frac{d}{d x} (\frac{x ^{3} + 14 x - 7}{7})

What is the integral of cosh(x/(27.2632)) ?
The integral of cosh(x/(27.2632)) is 27.2632sinh(0.03667…x)+C