What is the first derivative of ln(e^4) ?

The first derivative of ln(e^4) is 0

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derivative of ln(e^4)

\frac{d}{d x} (ln (e^{4}))

0

Solution steps

\frac{d}{d x} (ln (e^{4}))

ln (e^{4}) = 4

= \frac{d}{d x} (4)

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

\frac{d}{d x} (5 x^{3} - x^{- \frac{2}{5}})

x \to 0 lim (12 + x^{2} ln (x))

\frac{d}{d x} (\frac{5 x ^{2} - 9 x + 7}{3 x + 2})

\int (5 x^{2} + 7 x^{- 2}) d x

\frac{d y}{d x} = \frac{y ^{2}}{1 + x ^{2}}