What is the derivative of ln(x+a) ?

The derivative of ln(x+a) is 1/(x+a)

What is the first derivative of ln(x+a) ?

The first derivative of ln(x+a) is 1/(x+a)

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\frac{d}{d x} (ln (x + a))

\frac{1}{x + a}

Solution steps

\frac{d}{d x} (ln (x + a))

Apply the chain rule:

\frac{1}{x + a} \frac{d}{d x} (x + a)

= \frac{1}{x + a} \frac{d}{d x} (x + a)

\frac{d}{d x} (x + a) = 1

= \frac{1}{x + a} \cdot 1

Simplify

= \frac{1}{x + a}

\int \frac{( 2 x + 1 )}{x + 4} d x

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What is the derivative of ln(x+a) ?
The derivative of ln(x+a) is 1/(x+a)
What is the first derivative of ln(x+a) ?
The first derivative of ln(x+a) is 1/(x+a)