What is the derivative of y= 1/(1-x) ?

The derivative of y= 1/(1-x) is 1/((1-x)^2)

What is the first derivative of y= 1/(1-x) ?

The first derivative of y= 1/(1-x) is 1/((1-x)^2)

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derivative of

y = \frac{1}{1 - x}

\frac{1}{( 1 - x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{1 - x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((1 - x)^{- 1})

Apply the chain rule:

- \frac{1}{( 1 - x ) ^{2}} \frac{d}{d x} (1 - x)

= - \frac{1}{( 1 - x ) ^{2}} \frac{d}{d x} (1 - x)

\frac{d}{d x} (1 - x) = - 1

= - \frac{1}{( 1 - x ) ^{2}} (- 1)

Simplify

= \frac{1}{( 1 - x ) ^{2}}

\frac{x ^{2} + 5}{x}

x \to 4 lim (lo g_{2} (x))

\frac{\partial}{\partial x} (x^{2} + 2 x y - y^{2})

\int 1 + 100 x^{2} d x

What is the derivative of y= 1/(1-x) ?
The derivative of y= 1/(1-x) is 1/((1-x)^2)
What is the first derivative of y= 1/(1-x) ?
The first derivative of y= 1/(1-x) is 1/((1-x)^2)