What is (\partial)/(\partial y)(e^x*cos(y)) ?

The answer to (\partial)/(\partial y)(e^x*cos(y)) is -e^xsin(y)

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(\partial)/(\partial y)(e^x*cos(y))

\frac{\partial}{\partial y} (e^{x} \cdot cos (y))

- e^{x} sin (y)

Solution steps

\frac{\partial}{\partial y} (e^{x} cos (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= e^{x} \frac{\partial}{\partial y} (cos (y))

Apply the common derivative:

\frac{\partial}{\partial y} (cos (y)) = - sin (y)

= e^{x} (- sin (y))

Simplify

= - e^{x} sin (y)

ln (2 x), 1

\frac{\partial}{\partial x} (e^{x} cos (θ))

f (x) = x^{4} - 6 x^{2} - x, at x = 1, y = 6

\int_{0}^{1} x^{2} (2 (1 - x)) d x

\frac{d}{d x} (2 x (6 x - 18)^{6})

What is (\partial)/(\partial y)(e^x*cos(y)) ?
The answer to (\partial)/(\partial y)(e^x*cos(y)) is -e^xsin(y)