What is the derivative of ((x^2-3x))/(x^2+7x) ?

The derivative of ((x^2-3x))/(x^2+7x) is (10)/((x+7)^2)

What is the first derivative of ((x^2-3x))/(x^2+7x) ?

The first derivative of ((x^2-3x))/(x^2+7x) is (10)/((x+7)^2)

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derivative of

\frac{( x ^{2} - 3 x )}{x ^{2} + 7 x}

\frac{10}{( x + 7 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 3 x}{x ^{2} + 7 x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 3 x ) ( x ^{2} + 7 x ) - \frac{d}{d x} ( x ^{2} + 7 x ) ( x ^{2} - 3 x )}{( x ^{2} + 7 x ) ^{2}}

\frac{d}{d x} (x^{2} - 3 x) = 2 x - 3

\frac{d}{d x} (x^{2} + 7 x) = 2 x + 7

= \frac{( 2 x - 3 ) ( x ^{2} + 7 x ) - ( 2 x + 7 ) ( x ^{2} - 3 x )}{( x ^{2} + 7 x ) ^{2}}

Simplify

\frac{( 2 x - 3 ) ( x ^{2} + 7 x ) - ( 2 x + 7 ) ( x ^{2} - 3 x )}{( x ^{2} + 7 x ) ^{2}} : \frac{10}{( x + 7 ) ^{2}}

= \frac{10}{( x + 7 ) ^{2}}

y = 9 - x

\frac{d}{d x} (x (4 - x^{2})^{2})

\int \frac{1}{16 - x ^{2}} d x

\int 4 x d x

y^{^{''}} - 4 y = 4 e^{2 x}

What is the derivative of ((x^2-3x))/(x^2+7x) ?
The derivative of ((x^2-3x))/(x^2+7x) is (10)/((x+7)^2)
What is the first derivative of ((x^2-3x))/(x^2+7x) ?
The first derivative of ((x^2-3x))/(x^2+7x) is (10)/((x+7)^2)