What is (\partial)/(\partial y)(3e^xcos(yz)) ?

The answer to (\partial)/(\partial y)(3e^xcos(yz)) is -3e^xzsin(yz)

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(\partial)/(\partial y)(3e^xcos(yz))

\frac{\partial}{\partial y} (3 e^{x} cos (yz))

- 3 e^{x} z sin (yz)

Solution steps

\frac{\partial}{\partial y} (3 e^{x} cos (yz))

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 e^{x} \frac{\partial}{\partial y} (cos (yz))

Apply the chain rule:

- sin (yz) \frac{\partial}{\partial y} (yz)

= - sin (yz) \frac{\partial}{\partial y} (yz)

\frac{\partial}{\partial y} (yz) = z

= 3 e^{x} (- sin (yz) z)

Simplify

= - 3 e^{x} z sin (yz)

y = cos^{2} (x)

x y^{^{'}} - y = x^{3}

f (x) = - x

\int \frac{256 - x ^{2}}{x} d x

\int \frac{x}{( x ^{2} + 1 ) 1 - x ^{4}} d x

What is (\partial)/(\partial y)(3e^xcos(yz)) ?
The answer to (\partial)/(\partial y)(3e^xcos(yz)) is -3e^xzsin(yz)