What is the tangent of (x^2)/(x-2) ?

The tangent of (x^2)/(x-2) is y=(a_{0}^2-4a_{0})/((a_{0)-2)^2}x+(2a_{0}^2)/((a_{0)-2)^2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of (x^2)/(x-2)

tangent of

\frac{x ^{2}}{x - 2}

y = \frac{a _{0}^{2} - 4 a _{0}}{( a _{0} - 2 ) ^{2}} x + \frac{2 a _{0}^{2}}{( a _{0} - 2 ) ^{2}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{a _{0}^{2}}{a _{0} - 2})

Find the slope of

y = \frac{x ^{2}}{x - 2} : \frac{d y}{d x} = \frac{x ^{2} - 4 x}{( x - 2 ) ^{2}}

Compute the slope of

y = \frac{x ^{2}}{x - 2}

x = a_{0} : m = \frac{a _{0}^{2} - 4 a _{0}}{( a _{0} - 2 ) ^{2}}

Find the line with slope m=

\frac{a _{0}^{2} - 4 a _{0}}{( a _{0} - 2 ) ^{2}}

and passing through

(a_{0}, \frac{a _{0}^{2}}{a _{0} - 2}) : y = \frac{a _{0}^{2} - 4 a _{0}}{( a _{0} - 2 ) ^{2}} x + \frac{2 a _{0}^{2}}{( a _{0} - 2 ) ^{2}}

y = \frac{a _{0}^{2} - 4 a _{0}}{( a _{0} - 2 ) ^{2}} x + \frac{2 a _{0}^{2}}{( a _{0} - 2 ) ^{2}}

\int tan (m x) sec^{2} (m x) d x

x \to 3 lim (\frac{\frac{3}{x} - 1}{x - 3})

\int_{1}^{\infty} \frac{2}{x ^{3}} d x

2 y^{^{''}} + 4 y = 0

\frac{d}{d x} (\frac{1}{x ( 1 + ln ( x ) )})

What is the tangent of (x^2)/(x-2) ?
The tangent of (x^2)/(x-2) is y=(a_{0}^2-4a_{0})/((a_{0)-2)^2}x+(2a_{0}^2)/((a_{0)-2)^2}