What is (\partial)/(\partial x)(sin(-6x-3y)) ?

The answer to (\partial)/(\partial x)(sin(-6x-3y)) is -cos(3y+6x)*6

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(\partial)/(\partial x)(sin(-6x-3y))

\frac{\partial}{\partial x} (sin (- 6 x - 3 y))

- cos (3 y + 6 x) \cdot 6

Solution steps

\frac{\partial}{\partial x} (sin (- 6 x - 3 y))

Simplify

sin (- 6 x - 3 y) : - sin (3 y + 6 x)

= \frac{\partial}{\partial x} (- sin (3 y + 6 x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{\partial}{\partial x} (sin (3 y + 6 x))

Apply the chain rule:

cos (3 y + 6 x) \frac{\partial}{\partial x} (3 y + 6 x)

= cos (3 y + 6 x) \frac{\partial}{\partial x} (3 y + 6 x)

\frac{\partial}{\partial x} (3 y + 6 x) = 6

= - cos (3 y + 6 x) \cdot 6

y = 3 x + 5

n = 0 \sum \infty \frac{n}{8 ^{n}}

\int 14 x^{\frac{1}{3}} d x

\int 100 - 4 x^{2} d x

\frac{d}{d x} (3 ln (cos (x)))

What is (\partial)/(\partial x)(sin(-6x-3y)) ?
The answer to (\partial)/(\partial x)(sin(-6x-3y)) is -cos(3y+6x)*6