What is the integral from 0 to 5/12 of 60x ?

The integral from 0 to 5/12 of 60x is 125/24

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integral from 0 to 5/12 of 60x

\int_{0}^{\frac{5}{12}} 60 x d x

\frac{125}{24}

Decimal Notation

5.20833 \dots

Solution steps

\int_{0}^{\frac{5}{12}} 60 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 60 \cdot \int_{0}^{\frac{5}{12}} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{\frac{5}{12}}

= 60 [\frac{x ^{2}}{2}]_{0}^{\frac{5}{12}}

Compute the boundaries:

\frac{25}{288}

= 60 \cdot \frac{25}{288}

Simplify

= \frac{125}{24}

\frac{d}{d x} (e^{2 x} - e^{2})

(1 + x)^{- \frac{3}{5}}

x \to 7 lim (\frac{x + 7}{∣ x + 7 ∣})

x \to 2 lim (x^{4} - 8)

\int (sec (5 θ) tan (5 θ) + csc^{2} (2 θ)) d θ

What is the integral from 0 to 5/12 of 60x ?
The integral from 0 to 5/12 of 60x is 125/24