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Popular >

integral from 0 to 2 of |1-x|

Solution

\int_{0}^{2} ∣ 1 - x ∣ d x

Solution

1

Solution steps

\int_{0}^{2} ∣ 1 - x ∣ d x

Eliminate Absolutes

= \int_{0}^{1} 1 - x d x + \int_{1}^{2} - 1 + x d x

\int_{0}^{1} 1 - x d x = \frac{1}{2}

\int_{1}^{2} - 1 + x d x = \frac{1}{2}

= \frac{1}{2} + \frac{1}{2}

Simplify

\frac{1}{2} + \frac{1}{2} : 1

= 1

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of |1-x| ?
The integral from 0 to 2 of |1-x| is 1