What is the tangent of f(x)=16sqrt(x),\at x=4 ?

The tangent of f(x)=16sqrt(x),\at x=4 is y=4x+16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=16sqrt(x),\at x=4

tangent of

f (x) = 16 x, at x = 4

y = 4 x + 16

Solution steps

Find the tangent point:

(4, 32)

Find the slope of

f (x) = 16 x : \frac{df ( x )}{d x} = \frac{8}{x}

Compute the slope of

f (x) = 16 x

x = 4 : m = 4

Find the line with slope m=

4

and passing through

(4, 32) : y = 4 x + 16

y = 4 x + 16

\int_{3}^{2} (5 x^{2} + 4 x + 9) d x

y^{^{''}} + 4 y = 5 sec (2 t)

y^{^{''}} (e^{x} + 1) + y^{^{'}} = 0

\int x^{3} \cdot 4 - x^{2} d x

\frac{4}{3} π r^{2}

What is the tangent of f(x)=16sqrt(x),\at x=4 ?
The tangent of f(x)=16sqrt(x),\at x=4 is y=4x+16