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Popular >

y^'=3x+y,y(0)=7

Solution

y^{^{'}} = 3 x + y, y (0) = 7

Solution

y = - 3 (x + 1) + 10 e^{x}

Solution steps

y^{'} (x) = 3 x + y

Solve linear ODE:

y = - 3 (x + 1) + 10 e^{x}

y = - 3 (x + 1) + 10 e^{x}

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Frequently Asked Questions (FAQ)

What is the solution for y^'=3x+y,y(0)=7 ?
The solution for y^'=3x+y,y(0)=7 is y=-3(x+1)+10e^x