What is the derivative of ln(x+(x-1)/x) ?

The derivative of ln(x+(x-1)/x) is 1/x+1/(x^2)

What is the first derivative of ln(x+(x-1)/x) ?

The first derivative of ln(x+(x-1)/x) is 1/x+1/(x^2)

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\frac{d}{d x} (ln (x) + \frac{x - 1}{x})

\frac{1}{x} + \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (ln (x) + \frac{x - 1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (ln (x)) + \frac{d}{d x} (\frac{x - 1}{x})

\frac{d}{d x} (ln (x)) = \frac{1}{x}

\frac{d}{d x} (\frac{x - 1}{x}) = \frac{1}{x ^{2}}

= \frac{1}{x} + \frac{1}{x ^{2}}

\int cos (- 3 x) d x

x y^{3} + 5 x y = 36, (6, 1)

\frac{\partial}{\partial x} (3 e x sin (y))

\int (x^{3} + 2) d x

\int - \frac{sin ^{2} ( x )}{cos ( x )} d x

What is the derivative of ln(x+(x-1)/x) ?
The derivative of ln(x+(x-1)/x) is 1/x+1/(x^2)
What is the first derivative of ln(x+(x-1)/x) ?
The first derivative of ln(x+(x-1)/x) is 1/x+1/(x^2)