What is the derivative of sqrt(t)(a+bt) ?

The derivative of sqrt(t)(a+bt) is 0

What is the first derivative of sqrt(t)(a+bt) ?

The first derivative of sqrt(t)(a+bt) is 0

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\frac{d}{d x} (t (a + b t))

0

Solution steps

\frac{d}{d x} (t (a + b t))

Treat

a, b, t

as a constant

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

y^{^{''}} + 3 y^{^{'}} + 2 y = \frac{1}{4 + e ^{x}}

x \to 2 + lim (e^{(\frac{3}{2 - x})})

\frac{d}{d x} (\frac{3 + 2 x}{5 - 8 x})

\frac{d}{d x} (3 cos (x) - cos (3 x))

\frac{d}{d x} (x^{2 π})

What is the derivative of sqrt(t)(a+bt) ?
The derivative of sqrt(t)(a+bt) is 0
What is the first derivative of sqrt(t)(a+bt) ?
The first derivative of sqrt(t)(a+bt) is 0