What is the derivative of 5/(x^2-2) ?

The derivative of 5/(x^2-2) is -(10x)/((x^2-2)^2)

What is the first derivative of 5/(x^2-2) ?

The first derivative of 5/(x^2-2) is -(10x)/((x^2-2)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{5}{x ^{2} - 2})

- \frac{10 x}{( x ^{2} - 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{5}{x ^{2} - 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (\frac{1}{x ^{2} - 2})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 5 \frac{d}{d x} ((x^{2} - 2)^{- 1})

Apply the chain rule:

- \frac{1}{( x ^{2} - 2 ) ^{2}} \frac{d}{d x} (x^{2} - 2)

= - \frac{1}{( x ^{2} - 2 ) ^{2}} \frac{d}{d x} (x^{2} - 2)

\frac{d}{d x} (x^{2} - 2) = 2 x

= 5 (- \frac{1}{( x ^{2} - 2 ) ^{2}} \cdot 2 x)

Simplify

5 (- \frac{1}{( x ^{2} - 2 ) ^{2}} \cdot 2 x) : - \frac{10 x}{( x ^{2} - 2 ) ^{2}}

= - \frac{10 x}{( x ^{2} - 2 ) ^{2}}

\int v^{- 2} (2 v^{4} + 3 v^{2} - 2 v^{- 3}) d v

\frac{\partial}{\partial x} (x^{3} + e^{y^{2}})

y^{^{'}} + y = sin (x)

x \to 5 lim (ln (\frac{x}{5}))

n = 1 \sum \infty n

What is the derivative of 5/(x^2-2) ?
The derivative of 5/(x^2-2) is -(10x)/((x^2-2)^2)
What is the first derivative of 5/(x^2-2) ?
The first derivative of 5/(x^2-2) is -(10x)/((x^2-2)^2)