What is the limit as x approaches 1+of 4/(x^3-1) ?

The limit as x approaches 1+of 4/(x^3-1) is infinity

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limit as x approaches 1+of 4/(x^3-1)

x \to 1 + lim (\frac{4}{x ^{3} - 1})

\infty

Solution steps

x \to 1 + lim (\frac{4}{x ^{3} - 1})

For

x

approaching

1

from the right

, x > 1 \Rightarrow x^{3} - 1 > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

\int 3 x^{2} (x^{3} + 4)^{4} d x

f (x) = ln (sin (2 x))

y = 5 x^{2}, y = 30 x - 45, [0, 3]

\frac{d y}{d t} + \frac{3}{t} y = 3 t^{2} y^{2}

\frac{5 s}{( s ^{2} + 1 ) ^{2}}

What is the limit as x approaches 1+of 4/(x^3-1) ?
The limit as x approaches 1+of 4/(x^3-1) is infinity