What is the integral of 3\sqrt[5]{x} ?

The integral of 3\sqrt[5]{x} is 5/2 x^{6/5}+C

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integral of 3\sqrt[5]{x}

\frac{5}{2} x^{\frac{6}{5}} + C

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply the Power Rule

: \frac{5}{6} x^{\frac{6}{5}}

= 3 \cdot \frac{5}{6} x^{\frac{6}{5}}

Simplify

3 \cdot \frac{5}{6} x^{\frac{6}{5}} : \frac{5}{2} x^{\frac{6}{5}}

= \frac{5}{2} x^{\frac{6}{5}}

Add a constant to the solution

= \frac{5}{2} x^{\frac{6}{5}} + C

\frac{d}{d x} ((3 x - 1) (x - 2)^{4})

\frac{d y}{d x} (1 + x) - x y = x + x^{2}

y = 2 x sin (x)

x \to 0 lim (\frac{4 x}{∣ x ∣})

y^{^{''}} - 8 y^{^{'}} = 5 t

What is the integral of 3\sqrt[5]{x} ?
The integral of 3\sqrt[5]{x} is 5/2 x^{6/5}+C