en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'+y=e^{6t}

Solution

y^{^{'}} + y = e^{6 t}

Solution

y = \frac{e ^{6 t}}{7} + \frac{c _{1}}{e ^{t}}

Solution steps

y^{'} (t) + y = e^{6 t}

Solve linear ODE:

y = \frac{e ^{6 t}}{7} + \frac{c _{1}}{e ^{t}}

y = \frac{e ^{6 t}}{7} + \frac{c _{1}}{e ^{t}}

Popular Examples

derivative of ln(x+sqrt(x^2+4))derivative of

ln (x + x^{2} + 4)

(3x+2y+1)*dx-(3x+2y-1)*dy=0

(3 x + 2 y + 1) \cdot d x - (3 x + 2 y - 1) \cdot d y = 0

integral of (2x^4+3x^3-x)/(x^3)

\int \frac{2 x ^{4} + 3 x ^{3} - x}{x ^{3}} d x

tangent of f(x)=sqrt(x+7),\at x=-6 tangent of

f (x) = x + 7, at x = - 6

derivative of 4^{-x/4}

\frac{d}{d x} (4^{- \frac{x}{4}})

Frequently Asked Questions (FAQ)

What is the solution for y^'+y=e^{6t} ?
The solution for y^'+y=e^{6t} is y=(e^{6t})/7+(c_{1})/(e^t)