What is the derivative of 3x^2+2x-4 ?

The derivative of 3x^2+2x-4 is 6x+2

What is the first derivative of 3x^2+2x-4 ?

The first derivative of 3x^2+2x-4 is 6x+2

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\frac{d}{d x} (3 x^{2} + 2 x - 4)

6 x + 2

Solution steps

\frac{d}{d x} (3 x^{2} + 2 x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (2 x) - \frac{d}{d x} (4)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (4) = 0

= 6 x + 2 - 0

Simplify

= 6 x + 2

\int \frac{x}{( 4 + x ^{2} )} d x

\int \frac{( 3 t - 2 )}{t + 1} d t

\frac{3}{x ^{5}}

y^{^{'}} + 5 y = 15

\frac{\partial}{\partial x} (- x - sin (y^{2}))

What is the derivative of 3x^2+2x-4 ?
The derivative of 3x^2+2x-4 is 6x+2
What is the first derivative of 3x^2+2x-4 ?
The first derivative of 3x^2+2x-4 is 6x+2