What is the derivative of x-0.8-0.2*sin(x) ?

The derivative of x-0.8-0.2*sin(x) is -0.2cos(x)+1

What is the first derivative of x-0.8-0.2*sin(x) ?

The first derivative of x-0.8-0.2*sin(x) is -0.2cos(x)+1

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\frac{d}{d x} (x - 0.8 - 0.2 \cdot sin (x))

- 0.2 cos (x) + 1

Solution steps

\frac{d}{d x} (x - 0.8 - 0.2 sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (0.8) - \frac{d}{d x} (0.2 sin (x))

\frac{d x}{d x} = 1

\frac{d}{d x} (0.8) = 0

\frac{d}{d x} (0.2 sin (x)) = 0.2 cos (x)

= 1 - 0 - 0.2 cos (x)

Simplify

= - 0.2 cos (x) + 1

\frac{d}{d x} (- \frac{( 2 x ^{2} + 1 )}{( 1 - x ^{2} ) ^{\frac{5}{2}}})

x \frac{d y}{d x} = y^{2}

sin (4 x)

\int - \frac{e ^{4 x}}{4 x} d x

\int \frac{cos ( 4 x )}{2 + sin ( 4 x )} d x

What is the derivative of x-0.8-0.2*sin(x) ?
The derivative of x-0.8-0.2*sin(x) is -0.2cos(x)+1
What is the first derivative of x-0.8-0.2*sin(x) ?
The first derivative of x-0.8-0.2*sin(x) is -0.2cos(x)+1