What is laplacetransform sin(4t+5pi) ?

The answer to laplacetransform sin(4t+5pi) is -4/(s^2+16)

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laplacetransform sin(4t+5pi)

laplace transform

sin (4 t + 5 π)

- \frac{4}{s ^{2} + 16}

Solution steps

L {sin (4 t + 5 π)}

Use Laplace Transform table:

L {sin (a t + b)} = \frac{s \cdot sin ( b ) + a \cdot cos ( b )}{s ^{2} + a ^{2}}

L {sin (4 t + 5 π)} = \frac{s sin ( 5 π ) + 4 cos ( 5 π )}{s ^{2} + 4 ^{2}}

= \frac{s sin ( 5 π ) + 4 cos ( 5 π )}{s ^{2} + 4 ^{2}}

= - \frac{4}{s ^{2} + 16}

\int \frac{x ^{2}}{2} y + \frac{x}{2} y^{2} cos (z) d z

\frac{\partial}{\partial u} (e^{u})

\int_{2}^{3} \frac{x}{x ^{2} + 4 x + 20} d x

\frac{\partial}{\partial x} (\frac{x ^{2}}{x + y})

x \cdot ln (x)

What is laplacetransform sin(4t+5pi) ?
The answer to laplacetransform sin(4t+5pi) is -4/(s^2+16)