What is laplacetransform sin(t-((2*pi))/3) ?

The answer to laplacetransform sin(t-((2*pi))/3) is (-sqrt(3)s-1)/(2(s^2+1))

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laplacetransform sin(t-((2*pi))/3)

laplace transform

sin (t - \frac{( 2 \cdot π )}{3})

\frac{- 3 s - 1}{2 ( s ^{2} + 1 )}

Solution steps

L {sin (t - \frac{( 2 π )}{3})}

Use Laplace Transform table:

L {sin (a t + b)} = \frac{s \cdot sin ( b ) + a \cdot cos ( b )}{s ^{2} + a ^{2}}

L {sin (t - \frac{2 π}{3})} = \frac{s sin ( - \frac{2 π}{3} ) + 1 \cdot cos ( - \frac{2 π}{3} )}{s ^{2} + 1 ^{2}}

= \frac{s sin ( - \frac{2 π}{3} ) + 1 \cdot cos ( - \frac{2 π}{3} )}{s ^{2} + 1 ^{2}}

= \frac{- 3 s - 1}{2 ( s ^{2} + 1 )}

(- 3 x + 2)^{4} (- 2 x + 3)^{3}

x \to 0 lim (\frac{2 tan ( \frac{x}{2} )}{x})

\int tan^{5} (6 x) sec^{2} (6 x) d x

\frac{d}{d x} (\frac{1}{9 x ^{\frac{8}{9}}})

f (x) = ln (5) x^{4}

What is laplacetransform sin(t-((2*pi))/3) ?
The answer to laplacetransform sin(t-((2*pi))/3) is (-sqrt(3)s-1)/(2(s^2+1))