What is (\partial)/(\partial x)(7-x^2+xy-2y^2) ?

The answer to (\partial)/(\partial x)(7-x^2+xy-2y^2) is y-2x

Popular >

(\partial)/(\partial x)(7-x^2+xy-2y^2)

\frac{\partial}{\partial x} (7 - x^{2} + x y - 2 y^{2})

y - 2 x

Solution steps

\frac{\partial}{\partial x} (7 - x^{2} + x y - 2 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (7) - \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (x y) - \frac{\partial}{\partial x} (2 y^{2})

\frac{\partial}{\partial x} (7) = 0

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (2 y^{2}) = 0

= 0 - 2 x + y - 0

Simplify

= y - 2 x

\frac{d}{d x} (6 x^{- 2})

4 x - x^{2}, (1.3)

f (x) = 5 x^{4} - 6 x^{2} + 1

\frac{\partial}{\partial x} (2 x y - 3)

\frac{\partial}{\partial x} (\frac{4}{( x + 2 ) ^{2}})

What is (\partial)/(\partial x)(7-x^2+xy-2y^2) ?
The answer to (\partial)/(\partial x)(7-x^2+xy-2y^2) is y-2x