What is area 9x^4-9x^2,10x^2 ?

The answer to area 9x^4-9x^2,10x^2 is (1444sqrt(19))/(405)

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area 9x^4-9x^2,10x^2

area

9 x^{4} - 9 x^{2}, 10 x^{2}

\frac{1444 19}{405}

Decimal Notation

15.54135 \dots

Solution steps

Apply the area formula:

\int_{- \frac{19}{3}}^{\frac{19}{3}} 9 x^{4} - 19 x^{2} d x

Solve

\int_{- \frac{19}{3}}^{\frac{19}{3}} 9 x^{4} - 19 x^{2} d x : \frac{1444 19}{405}

The area is:

= \frac{1444 19}{405}

\frac{d}{d x} ((\frac{1}{x ^{2}} - \frac{7}{x ^{4}}) (x + 3 x^{3}))

3 x - 3 x

\int \frac{2 1 + x ^{4}}{x ^{3}} d x

\int \frac{x}{( 1 - 3 x ^{2} )} d x

x^{^{''}} - x^{^{'}} = 0

What is area 9x^4-9x^2,10x^2 ?
The answer to area 9x^4-9x^2,10x^2 is (1444sqrt(19))/(405)