What is the derivative of (8x+9)(9x-10) ?

The derivative of (8x+9)(9x-10) is 144x+1

What is the first derivative of (8x+9)(9x-10) ?

The first derivative of (8x+9)(9x-10) is 144x+1

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derivative of

(8 x + 9) (9 x - 10)

144 x + 1

Solution steps

\frac{d}{d x} ((8 x + 9) (9 x - 10))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 8 x + 9, g = 9 x - 10

= \frac{d}{d x} (8 x + 9) (9 x - 10) + \frac{d}{d x} (9 x - 10) (8 x + 9)

\frac{d}{d x} (8 x + 9) = 8

\frac{d}{d x} (9 x - 10) = 9

= 8 (9 x - 10) + 9 (8 x + 9)

Simplify

8 (9 x - 10) + 9 (8 x + 9) : 144 x + 1

= 144 x + 1

\frac{d}{d x} (e^{- c o s (x)})

\frac{e ^{x}}{5 x + 3}

\int \frac{1}{( 4 x ^{2} - 9 ) ^{\frac{3}{2}}} d x

\int x^{2} sin (x^{3}) d x

\int x e^{- \frac{x ^{2}}{2}} d x

What is the derivative of (8x+9)(9x-10) ?
The derivative of (8x+9)(9x-10) is 144x+1
What is the first derivative of (8x+9)(9x-10) ?
The first derivative of (8x+9)(9x-10) is 144x+1