What is the solution for xy^'-y=x^3y^4 ?

The solution for xy^'-y=x^3y^4 is y=(\sqrt[3]{2}x)/(\sqrt[3]{-x^6+c_{1)}}

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xy^'-y=x^3y^4

x y^{^{'}} - y = x^{3} y^{4}

Solution steps

x y^{'} (x) - y = x^{3} y^{4}

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What is the solution for xy^'-y=x^3y^4 ?
The solution for xy^'-y=x^3y^4 is y=(\sqrt[3]{2}x)/(\sqrt[3]{-x^6+c_{1)}}