derivative of 25x^3-6x^2+7x-88

解答

\frac{d}{d x} (25 x^{3} - 6 x^{2} + 7 x - 88)

75 x^{2} - 12 x + 7

求解步骤

\frac{d}{d x} (25 x^{3} - 6 x^{2} + 7 x - 88)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (25 x^{3}) - \frac{d}{d x} (6 x^{2}) + \frac{d}{d x} (7 x) - \frac{d}{d x} (88)

\frac{d}{d x} (25 x^{3}) = 75 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (7 x) = 7

\frac{d}{d x} (88) = 0

= 75 x^{2} - 12 x + 7 - 0

化简

= 75 x^{2} - 12 x + 7

\frac{d y}{d x} = 0.1 y (1 - \frac{y}{500})

9 y^{^{''}} - 24 y^{^{'}} + 16 y = 0

d er i v a t i v e y = \frac{1}{( x ^{2} - 2 ) ( x ^{2} + x + 5 )}

t an g e n t y = 5 x cos (x), (π, - 5 π)

d er i v a t i v e y = csc^{3} (2 x)