What is the solution for (dy)/(dx)=(8+x)^2 ?

The solution for (dy)/(dx)=(8+x)^2 is y=64x+8x^2+(x^3)/3+c_{1}

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(dy)/(dx)=(8+x)^2

\frac{d y}{d x} = (8 + x)^{2}

y = 64 x + 8 x^{2} + \frac{x ^{3}}{3} + c_{1}

Solution steps

\frac{d y}{d x} = (8 + x)^{2}

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = (8 + x)^{2}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int (8 + x)^{2} d x

\int (8 + x)^{2} d x = 64 x + 8 x^{2} + \frac{x ^{3}}{3} + c_{1}

y = 64 x + 8 x^{2} + \frac{x ^{3}}{3} + c_{1}

\int \frac{3 x ^{2} - x + 4}{x ^{3} + 2 x ^{2} + 6 x} d x

\frac{d}{d x} (\frac{13}{ln ( x )})

x \to \infty lim (\frac{e ^{2 x} + e ^{x}}{e ^{2 x} - 1} 1)

\frac{1}{( s + 2 ) ( s - 1 ) ^{5}}

\int - 32

What is the solution for (dy)/(dx)=(8+x)^2 ?
The solution for (dy)/(dx)=(8+x)^2 is y=64x+8x^2+(x^3)/3+c_{1}