What is the integral of (2x+3)^{1/2} ?

The integral of (2x+3)^{1/2} is 1/3 (2x+3)^{3/2}+C

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integral of (2x+3)^{1/2}

\int (2 x + 3)^{\frac{1}{2}} d x

\frac{1}{3} (2 x + 3)^{\frac{3}{2}} + C

Solution steps

\int (2 x + 3)^{\frac{1}{2}} d x

Apply u-substitution

: \int \frac{u ^{\frac{1}{2}}}{2} d u

= \int \frac{u ^{\frac{1}{2}}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int u^{\frac{1}{2}} d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= \frac{1}{2} \cdot \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = 2 x + 3

= \frac{1}{2} \cdot \frac{2}{3} (2 x + 3)^{\frac{3}{2}}

Simplify

\frac{1}{2} \cdot \frac{2}{3} (2 x + 3)^{\frac{3}{2}} : \frac{1}{3} (2 x + 3)^{\frac{3}{2}}

= \frac{1}{3} (2 x + 3)^{\frac{3}{2}}

Add a constant to the solution

= \frac{1}{3} (2 x + 3)^{\frac{3}{2}} + C

\frac{d}{d x} (\frac{x ^{4}}{16} + \frac{1}{2 x ^{2}})

y = arccos (e^{3 x})

cos (3 x), 2 - cos (x)

f (x) = x^{3} - 3 x^{2} - 45 x + 5

(1 - \frac{1}{x})^{^{'}}

What is the integral of (2x+3)^{1/2} ?
The integral of (2x+3)^{1/2} is 1/3 (2x+3)^{3/2}+C