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Popular >

y^'+xe^y=0

Solution

y^{^{'}} + x e^{y} = 0

Solution

y = - ln (\frac{x ^{2}}{2} - c_{1})

Solution steps

y^{'} (x) + x e^{y} = 0

Solve separable ODE:

y = - ln (\frac{x ^{2}}{2} - c_{1})

y = - ln (\frac{x ^{2}}{2} - c_{1})

Popular Examples

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\int e^{x} 5 + e^{x} d x

derivative of f(x)=3sqrt(x)sin(x)derivative of

f (x) = 3 x sin (x)

derivative of f(x)=(8x^3-2x+9)/x derivative of

f (x) = \frac{8 x ^{3} - 2 x + 9}{x}

inverse oflaplace (10s+3)/(s^2+4s+29)inverse laplace

\frac{10 s + 3}{s ^{2} + 4 s + 29}

limit as x approaches 0 of (2x-8)^{1/3}

x \to 0 lim ((2 x - 8)^{\frac{1}{3}})

Frequently Asked Questions (FAQ)

What is the solution for y^'+xe^y=0 ?
The solution for y^'+xe^y=0 is y=-ln((x^2)/2-c_{1})